2016-II-37
Ans: A
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By comparing the given figure to the graph of $y=\cos x

By comparing the given figure to the graph of $y=\cos x

Consider $\Delta ABC$,
$\begin{array}{rcl}
AC^2

Join $BD$. Consider $\Delta PBD$, we have
$\begin{ar
$\begin{array}{cl}
=
$\begin{array}{cl}
= & C^{
$\begin{array}{cl}
= & 4^2 \ti
