HKDSE-MATH

2018-I-08

Ans: $x = 180^\circ – \theta$, $y = 2\theta – 18

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2018

2018-I-09

Ans: $1.75$ hours
Let $x \text{hours}$ be the time needed fr

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2018

2018-I-10

Ans: (a) $a = 48$, $b = 62$ (b) No

Since the range of the distrib

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2018

2018-I-11

Ans: (a) (i) $1$ (ii) $8$ (b) (i) $3$ (ii) $19$ (c) $9$

1. Since $k

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2018

2018-I-12

Ans: (a) $a = -19$, $b = -135$ (b) No

Since $x – 3$ is a fac

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2018

2018-I-13

Ans: (b) (i) $48\text{ cm}$ (ii) $750\text{ cm}^2$ (iii) No

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2018

2018-I-14

Ans: (a) $4096\pi\text{ cm}^3$ (b) $48\text{ cm}$ (c) No

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2018

2018-I-15

Ans: (a) $40320$ (b) $8640$

The required number
$\begin{ar

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2018

2018-I-16

Ans: (a) $500$ (b) $75$

Let $a$ and $r$ be the 1st term and the c

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2018

2018-I-17

Ans: (a) $31.9\text{ cm}$ (b) (i) $38.0^\circ$ (ii) $71.9^

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2018

2018-I-18

Ans: (a) $f(x) = 3x^2 + 24x$ (b) (i) $(-4, -48)$ (ii) $(-4, 75)

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2018

2018-I-19

Ans: (a) $C: (x – 8)^2 + (y – 2)^2 = r^2$, $r^2 = \d

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2018

2018-II-01

Ans: B
$\begin{array}{cl}
& \dfrac{8^{2n+1}}{4^{3

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2018

2018-II-02

Ans: D
$\begin{array}{rcl}
\dfrac{\alpha}{1-x} & =

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2018

2018-II-03

Ans: C
$\begin{array}{cl}
& h^2 -6h – 4k^2 -12k

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2018

2018-II-04

Ans: A
$\begin{array}{cl}
& \dfrac{1}{3x + 7} –

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2018

2018-II-05

Ans: A
A is true. Rewrite the equation of the graph to $y = -(x &

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2018

2018-II-06

Ans: D
I is true. Consider the slope of $L_1$.

$\begin{array

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2018

2018-II-07

Ans: D
$\begin{array}{rcl}
f(2m – 1) & = &

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2018

2018-II-08

Ans: C
Since $g(x)$ is divisible by $x – 1$, by the fact

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2018