2020-II-21
Ans: C
In $\Delta BCE$,
… Read In $\Delta BCE$,
$\begin{array}{cl}
& BE^2 + BC
$\begin{array}{cl}
& BE^2 + BC

Consider $\Delta ABC$. Since $\an

Note that
$\begin{array}{cl}
= & \dfrac{
$\begin{array}{|c|c|c
I m

II is true. The gra
$\begin{array}{cl}

Sub. $x=

Note that $4
