2012-II-18
Ans: A
In $\Delta BCD$,
… Read In $\Delta BCD$,
$\begin{array}{rcl}
\sin \alpha
$\begin{array}{rcl}
\sin \alpha
$\begin{array}{rcl}
\mbox{reflex }\ang
$\begin{array}{cl}
=
$\begin{array}{cl}
=
$\begin{array}{cl}
= &
$\begin