2012PP-I-13
Ans: (a) $8$ (b) (i) $45^\circ$ (ii) No
… Read -
$\begin{array}{rcl
HKDSE-MATH
2012PP-I-14
Ans: (a) $\Delta DBC \sim \Delta DOA$ (b) (i) $(0,4)$ (ii) $(
… Read 2012PP-I-15
Ans: (a) $3$ (b) Smaller
… Read - Let $\sigma$ be the standard deviat
2012PP-I-16
Ans: (a) $\dfrac{68}{609}$ (b) $\dfrac{530}{609}$
… Read - The re
2012PP-I-17
Ans: (a) $\dfrac{1}{5}-\dfrac{2}{5}i$ (b) (i) $p=-4$, $q
… Read 2012PP-I-18
Ans: (a) $17.4\text{ cm}$ (b) $71.9^\circ$ (c) When $P$ mov
… Read 2012PP-I-19
Ans: (a) $36$ (b) (i) $11$ years (ii) No (iii) No
… Read -
$\begin{arr
2012PP-II-01
Ans: A
$\begin{array}{cl}
& x^3(2x+x) \\
= & x^3
… Read $\begin{array}{cl}
& x^3(2x+x) \\
= & x^3
2012PP-II-02
Ans: C
$\begin{array}{rcl}
3a+1 & = & 3(b-2) \\
3
… Read $\begin{array}{rcl}
3a+1 & = & 3(b-2) \\
3
2012PP-II-03
Ans: A
$\begin{array}{cl}
& p^2 -q^2-p-q \\
= & (
… Read $\begin{array}{cl}
& p^2 -q^2-p-q \\
= & (
2012PP-II-04
Ans: D
$\begin{array}{rcl}
\mbox{LHS} & = & m(x-3
… Read $\begin{array}{rcl}
\mbox{LHS} & = & m(x-3
2012PP-II-05
Ans: D
By the remainder theorem, the remainder
… Read By the remainder theorem, the remainder
$\begin{arr
2012PP-II-06
Ans: C
The quadratic equation has equal roots, then $\Delta
… Read The quadratic equation has equal roots, then $\Delta
2012PP-II-07
Ans: B
I is true. $L_1$ is a vertical straight line and its $x$
… Read I is true. $L_1$ is a vertical straight line and its $x$
2012PP-II-08
Ans: D
I is false. According to the figure, the graph opens do
… Read I is false. According to the figure, the graph opens do
2012PP-II-09
Ans: A
$\begin{array}{rcl}
4x & & x-3 \\
3x &
… Read $\begin{array}{rcl}
4x & & x-3 \\
3x &
2012PP-II-10
Ans: B
The required price
… Read The required price
$\begin{array}{cl}
= & \$1~
2012PP-II-11
Ans: D
Let $c_0$ and $c_1$ be the original and new circumfere
… Read Let $c_0$ and $c_1$ be the original and new circumfere
2012PP-II-12
Ans: A
$\begin{array}{rcl}
(\alpha +\beta): (3\alpha-\b
… Read $\begin{array}{rcl}
(\alpha +\beta): (3\alpha-\b
2012PP-II-13
Ans: A
Note that $z=\dfrac{kx}{y^2}$, where $k$ is a non-ze
… Read Note that $z=\dfrac{kx}{y^2}$, where $k$ is a non-ze