HKDSE-MATH - 2012PP - Paper 2 -

Ans: (a) (i) ${53.1}^{\circ }$ (ii) $17.1\text{ cm}$ (b) (i) $28

Ans: B
Let $2x\text{ cm}$ be the length of a side of the tetrah

Ans: (a) ${35.7}^{\circ }$ (b) Yes

1. By applying sine law to $\Delt

Ans: D

Note that $\mathrm{\angle }AXB=\theta$. Consider $\Delta BCD

Ans: (a) (i) $42.9\text{ cm}$ (ii) ${66.6}^{\circ }$ (iii) The a

Ans: (a) $\mathrm{\angle }ABD={52.3}^{\circ }$, $CD=10.7\text{ cm}$ (b

Ans: A

Consider $\mathrm{\Delta }ABC$,

$\begin{array}{rcl}
AC^2 &#

Ans: (a) $45.7\text{ cm}$ (b) (i) $11.4\text{ cm}$ (ii) $45

Ans: A
Consider $\mathrm{\Delta }ABD$. Since $AD$ is a vertical pole,

Ans: (a) $31.9\text{ cm}$ (b) (i) ${38.0}^{\circ }$ (ii) $71.9^

Ans: D
On $AF$, add a point $Y$ such that $XY\perp AF$. Join $B

Ans: (a) (i) ${61.4}^{\circ }$ (ii) $11.4\text{ cm}$ (b) No

1. 1. By ap

Ans: C
In $\mathrm{\Delta }PQR$,

$\begin{array}{rcl}
\tan \angle PR

Ans: (a) $16.9\text{ cm}$ (b) $1400{\text{ cm}}^2$ (c) (i) $1

Ans: A
By applying Pythagoras Theorem to $\mathrm{\Delta }ABP$, we ha

Ans: (a) $36.7\text{ cm}$ (b) (i) ${35.5}^{\circ }$ (ii) Yes

1. Ske

Ans: (a) (i) $40.7\text{ cm}$ (ii) ${37.7}^{\circ }$ (b) No

1. 1. By us

Ans: A

Note that $\alpha =\mathrm{\angle }GFH={45}^{\circ }$.

Denote the

Ans: (a) ${51.5}^{\circ }$ (b) No

1. By applying the sine law to $\De