HKDSE-MATH - 2012PP - Paper 2 -

Ans: (a) (i) $53.1^\circ$ (ii) $17.1\text{ cm}$ (b) (i) $28

Ans: B
Let $2x\text{ cm}$ be the length of a side of the tetrah

Ans: (a) $35.7^\circ$ (b) Yes

1. By applying sine law to $\Delt

Ans: D

Note that $\angle AXB = \theta$. Consider $\Delta BCD

Ans: (a) (i) $42.9\text{ cm}$ (ii) $66.6^\circ$ (iii) The a

Ans: (a) $\angle ABD=52.3^\circ$, $CD=10.7\text{ cm}$ (b

Ans: A

Consider $\Delta ABC$,

$\begin{array}{rcl}
AC^2 &#

Ans: (a) $45.7\text{ cm}$ (b) (i) $11.4\text{ cm}$ (ii) $45

Ans: A
Consider $\Delta ABD$. Since $AD$ is a vertical pole,

Ans: (a) $31.9\text{ cm}$ (b) (i) $38.0^\circ$ (ii) $71.9^

Ans: D
On $AF$, add a point $Y$ such that $XY \perp AF$. Join $B

Ans: (a) (i) $61.4^\circ$ (ii) $11.4\text{ cm}$ (b) No

1. 1. By ap

Ans: C
In $\Delta PQR$,

$\begin{array}{rcl}
\tan \angle PR

Ans: (a) $16.9\text{ cm}$ (b) $1400\text{ cm}^2$ (c) (i) $1

Ans: A
By applying Pythagoras Theorem to $\Delta ABP$, we ha

Ans: (a) $36.7\text{ cm}$ (b) (i) $35.5^\circ$ (ii) Yes

1. Ske

Ans: (a) (i) $40.7\text{ cm}$ (ii) $37.7^\circ$ (b) No

1. 1. By us

Ans: A

Note that $\alpha = \angle GFH = 45^\circ$.

Denote the

Ans: (a) $51.5^\circ$ (b) No

1. By applying the sine law to $\De