HKDSE-MATH - 2016 - Paper 2 -

Ans: A
Consider the first inequality,

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Ans: (a) $1 < x \le 5$ (b) $4$

1. Consider $7(x-2) \le \dfrac{11x+8}{3}$, we hav

Ans: D
Consider $6-x < 2x -3$.

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6 – x &

Ans: (a) $-8 \le x < \dfrac{-11}{5}$ (b) $-3$

1. Consider $\dfrac{3-x}{2} 2x + 7$.

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Ans: C
Consider

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\dfrac{1-2x}{3} �

Ans: (a) $x \ge 2$ (b) $8$

1. $\begin{array}{rcl}
   \dfrac{7x + 2

Ans: B
Consider the first inequality.

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Ans: (a) $x \neq -1$ (b) $-2$

1. $\begin{array}{rcl}
   3 –

Ans: D
Consider $5-4x < 9$.

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5 – 4x �

Ans: (a) $-4 \le x < 7$ (b) $6$

1. Consider the first inequality, we have

   $\b

Ans: C

Consider the first inequality, we have

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Ans: (a) $x<-2$ (b) $-3$

1. Consider the first inequality, we have

   $\begin{

Ans: A

$\left\{ \begin{array}{ll}
3y-5 < 5y +1 & \ldots \unicode{x2460} \\ 5y +1 \le 11 & \ldots \unicode{x2461} \end{array}\right.$

From $\unicode{x2

Ans: (a) $\dfrac{-9}{2} < x < 3$ (b) $4$

1. Consider the first inequality, we

Ans: D

Consider the first inequality, we have

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