HKDSE-MATH - 2016 - Paper 2 -

$\begin{array}{rcl

1. Consider $7(x-2)\le {\displaystyle \frac{11x+8}{3}}$, we hav

$\begin{array}{rcl}
6 – x &

1. Consider ${\displaystyle \frac{3-x}{2}}2x+7$.

   $\begin

$\begin{array}{rcl}
\dfrac{1-2x}{3} �

1. $\begin{array}{rcl}
   \dfrac{7x + 2

$\begin{array}{rcl

1. $\begin{array}{rcl}
   3 –

$\begin{array}{rcl}
5 – 4x �

1. Consider the first inequality, we have

   $\b

Consider the first inequality, we have

$\begin{arra

1. Consider the first inequality, we have

   $\begin{

$\{\begin{array}{ll}3y-5<5y+1& \dots \text{①}\\ 5y+1\le 11& \dots \text{②}\end{array}$

From $\unicode{x2

1. Consider the first inequality, we

Consider the first inequality, we have

$\begin{arra