HKCEE - 2006 - Paper 1 -

Ans: (a) (ii) $a=2$, $b=3$ (b) $2x^2+3x-4$, $\dfrac{-3\pm

Ans: B
By the remainder theorem, we have

$\begin{array}{rc

Ans: (a) (i) $39$ (ii) $(x+3)(x+9)(4x-9)$ (b) (i) $C=16x^3

Ans: A
Since $f(x)$ is divisible by $(x-1)$, by the division

Ans: (a) $1$ and $3$ (b) $2$ and $3$

1. Note that $n$ is a positive

Ans: B
$\begin{array}{cl}
& (2x^2-3x+1) -2(x^2+2x-

Ans: A
$\begin{array}{rcl}
a(x^2 -x ) + b(x^2 + x) & \eq

Ans: A
Let $f(x) = x^{2009} + x^{2008} + \cdots + x$. Hence, th

Ans: D
$\begin{array}{rcl}
hx + (x-3)^2 & \equiv 

Ans: A
Let $f(x)=x^3+5x^2+3kx-k$. Since $f(x)$ is divisib

Ans: D
Since $f(x)$ is divisible by $2x+1$, then by the facto