HKDSE-MATH - 2013 - Paper 1 -

Ans: (a) $a=3$, $b=-1$ and $c=4$ (b) No

1. Note that the remaind

Ans: A
$\begin{array}{rcl}
x(x+3a)+a & \equiv &

Ans: D
Since $f(x)$ is divisible by $x+1$, we have

$\begin{a

Ans: (a) Yes (b) Yes

1. When $f(x)$ is divided by $x-2$, the rema

Ans: B
$\begin{array}{rcl}
px(x-1)+x^2 & \equiv �

Ans: (a) $h=2$, $k=-5$ (b) No

1. By the remainder theorem, we ha

Ans: B
$\begin{array}{rcl}
x^2 + mx + n & \equiv &

Ans: (a) $l=3$, $m=-1$, $n=-4$ (b) $2$

1. Since when $p(x)$ is d

Ans: B
Since $f(x)$ is divisible by $2x+1$, we have

$\begin{

Ans: (a) $-9$ (b) (ii) No

1. By the division algorithm, we have

   $

Ans: B
Since $p(x)$ is divisible by $x-7$, then by the factor

Ans: A
$\begin{array}{rcl}
4x^2 + m(x+1) + 28 & \equiv

Ans: (a) $a = -19$, $b = -135$ (b) No

1. Since $x – 3$ is a fac

Ans: C
Since $g(x)$ is divisible by $x – 1$, by the fact

Ans: (a) $5x – 3$ (b) $1$

1. Since $p(x)$ is divisible by $

Ans: C
$\begin{array}{rcl}
(x-8)(x+ \alpha) – 6 �

Ans: D
Let $f(x) = 2x^4 +kx^3 -4x -16$. Since $f(x)$ is divisi

Ans: (a) $-8$ (b) Yes

1. According to the division algorithm, l

Ans: D
Since $x+2$ is a factor of $g(x)$, then by the factor th

Ans: C
$\begin{array}{rcl}
(x + h)(x+6) & \equiv