2021-I-12
Ans: (a) $-67$ (c) No
… Read - By the division algorithm, we have
$p(x
$\begin{array}{rcl}
a(x+3)+b(3x+1) & \equiv
Let $p(x) = (x^2-1)Q(x) +(ax+b)$, where $Q(x)$ is a po
$\begin{array}{rcl}
(x+3)^2+mx & \equiv
Since $g(x)$ is divisible by $x+2a$, we have
$\begin{
$\begin{array}{rcl}
(x+2)(x+c)+12 & \equiv &
Since $h(x)$ is divisible by $2x-3$, we have
$\begin{