Trigonometric Identities

08-07-202312-07-2023 app.cch No Comments

$\sin^2\theta+\cos^2\theta =1$
$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$
$\sin(-\theta)=-\sin\theta$
$\cos(-\theta)=\cos\theta$
$\tan(-\theta) = -\tan\theta$
$\sin (180^\circ-\theta)=\sin\theta$
$\cos (180^\circ-\theta)=-\cos\theta$
$\tan (180^\circ-\theta)=-\tan \theta$
$\sin (180^\circ+\theta)=-\sin\theta$
$\cos (180^\circ+\theta)=-\cos\theta$
$\tan (180^\circ+\theta)=\tan\theta$
$\sin (360^\circ – \theta) = -\sin\theta$
$\cos (360^\circ-\theta)=\cos\theta$
$\tan (360^\circ-\theta)=-\tan\theta$
$\sin (90^\circ-\theta)=\cos\theta$
$\cos (90^\circ-\theta) = \sin\theta$
$\tan(90^\circ-\theta) = \dfrac{1}{\tan\theta}$
$\sin(90^\circ+\theta)=\cos\theta$
$\cos(90^\circ+\theta)=-\sin\theta$
$\tan(90^\circ+\theta)=\dfrac{-1}{\tan\theta}$
$\sin(270^\circ-\theta)=-\cos\theta$
$\cos(270^\circ-\theta)=-\sin\theta$
$\tan(270^\circ-\theta)=\dfrac{1}{\tan\theta}$
$\sin(270^\circ+\theta)=-\cos\theta$
$\cos(270^\circ+\theta)=\sin\theta$
$\tan(270^\circ+\theta)=\dfrac{-1}{\tan\theta}$

Math, Measures, Shape and Space, Revision Note, Trigonometry

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