答案：$\angle ABE=70^\circ$, $\angle BCD=40^\circ$
因為 $BC//AD$，則可得
因為 $BC//AD$，則可得
$\begin{array}{rcl}
\angle AEB & = & \angle CBE \\
& = & 70^\circ
\end{array}$
因為 $AE = AB$，則可得
$\begin{array}{rcl}
\angle ABE & = & \angle AEB \\
& = & 70^\circ
\end{array}$
在 $\Delta ABE$ 中，
$\begin{array}{rcl}
\angle BAC & = & 180^\circ – \angle ABE – \angle AEB \\
& = & 180^\circ – 70^\circ – 70^\circ \\
& = & 40^\circ
\end{array}$
因為 $ABCD$ 為平行四邊形，則可得
$\begin{array}{rcl}
\angle BCD & = & \angle BAD \\
& = & 40^\circ
\end{array}$
