答案：$x=33^\circ$, $y=76^\circ$, $z=28^\circ$
由於 $AB//CD$，則
由於 $AB//CD$，則
$\begin{array}{rcl}
\angle ADC & = & \angle DAB \\
x & = & 33^\circ
\end{array}$
考慮 $\Delta CDE$，
$\begin{array}{rcl}
\angle CEA & = & \angle ECD + \angle EDC \\
y & = & 43^\circ + x \\
& = & 43^\circ + 33^\circ \\
&= & 76^\circ
\end{array}$
考慮 $\Delta ACE$，因為 $AE = AC$，可得
$\begin{array}{rcl}
\angle ACE & = & \angle AEC \\
& = & y \\
& = & 76^\circ
\end{array}$
所以，可得
$\begin{array}{rcl}
\angle CAE & = & 180^\circ – \angle ACE – \angle AEC \\
z & = & 180^\circ – 76^\circ – 76^\circ \\
& = & 28^\circ
\end{array}$
