答案：C
該直立角柱體的底面積
該直立角柱體的底面積
$\begin{array}{cl}
= & \dfrac{1}{2} \times (5 + 11) \times 8 \\
= & 64 \text{ cm}^2
\end{array}$
該直立角柱體的體積
$\begin{array}{cl}
= & 64 \times 6 \\
= & 384 \text{ cm}^3
\end{array}$
