2011-II-03 Posted on 20-06-2023 By app.cch 在〈2011-II-03〉中尚無留言 答案:D$\begin{array}{cl} & (x-2y)(x+2y-2) \\ = & x^2 +2xy-2x -2xy -4y^2 +4y \\ = & x^2 -4y^2 -2x + 4y \end{array}$ Same Topic: 2008-II-05 2009-I-03 2010-I-03 2011-I-03 2011, 卷二, 香港中學會考 Tags:因式分解