2017-I-17

15-06-2023 app.cch 尚無留言

答案：(a)

\frac{5}{3876}

(b)

\frac{35}{969}

(c)

\frac{3731}{3876}

所求概率
$\begin{array}{cl} = & \frac{C_{4}^{4} \times C_{1}^{15}}{C_{5}^{19}} \\ = & \frac{5}{3876} \end{array}$
所求概率
$\begin{array}{cl} = & \frac{C_{3}^{4} \times C_{1}^{15}}{C_{5}^{19}} \\ = & \frac{35}{969} \end{array}$
所求概率
$\begin{array}{cl} = & 1 - \frac{5}{3876} - \frac{35}{969} \\ = & \frac{3731}{3876} \end{array}$

2017, 卷一, 香港中學文憑-數學概率

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