Solving Master
Resources for HKDSE Mathematics
根據圖像,圓心的 $x$ 及 $y$ 坐標均為該圓的半徑。設 $I(r,r)$ 為
$\begin{array}{cl} = & C^{13}_5 \time
$\begin{array}{cl} = & 1 – 0.7^4 \\ =
$\begin{array}{rcl} \dfr