2014-II-26
答案:A
該圓的圓心的坐標
… Read 該圓的圓心的坐標
$\begin{array}{cl}
= & \left( –
$\begin{array}{cl}
= & \left( –
$\begin{array}{rcl}
$\begin{array}{cl}
= & \$ 240 \div \d
II 必為正確。留意該分佈的分佈域最小為 $33$。若 $
II 為正確。根據題目的圖像,$b$ 及 $c$ 均大於 $1$,所以 $bc1$。
$\begin{array}{
$\begin{array}{lllllll}
\dfrac{2^{2m}}{
留意 $\angle AXB = \theta$。考慮 $\Delta BCD$,根據畢氐定理,可得
$\
$\begin{array}{rcl}
\ang
$\begin{array}{cl}
= & C^{13}_2 \times C