香港中學會考 - 2006 - 卷二 -

答案：A
$\begin{array}{rcl}
f(3)f(\dfrac{1}{3}) & = &

答案：D
已知 $f(x)=x^2-ax+2a$。

$\begin{array}{rcl}
f(-3) �

答案：C
$\begin{array}{rcl}
f(4)-f(3) & = & 21 \\
(

答案：A
$\begin{array}{rcl}
f(-1) & = & 8 \\
(-1)^2

答案：C
$\begin{array}{rcl}
3f(2) – 1 & = & 3

答案：A
$\begin{array}{cl}
& f(5)-f(3) \\
= & (5)^

答案：A
$\begin{array}{cl}
& f(2) – f(-2) \\
= �

答案：D
$\begin{array}{rcl}
f(2m – 1) & = & 3

答案：C
$\begin{array}{cl}
& f(c) + f(-c) \\
= & [c^

答案：B
$\begin{array}{cl}
& f(1 + \beta) – f(1 &#

答案：A

已知 $f(x)=(x+h)(x-3) +k$。

$\begin{array}{rcl}
f(0) &

答案：B

A 不一定正確。留意 $f(k) = k^2 -k +1$。

$\begin{array}{rcl}
f(-

答案：D

$\begin{array}{cl}
& g(1-3\alpha) \\
= & 1